Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of a radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remainin

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Solution

Q.
Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of a radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remaining disc from the origin will be: [2025]

1 2.0 cm

2 0.5 cm

3 1.5 cm

4 1.0 cm

Ans.
(4)

M $\propto$ A

$x_{c m} = \frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}}$

$= \frac{A (0) + (- \frac{A}{16}) (15)}{A - \frac{A}{16}}$

$= \frac{- 15}{16 - 1} = - 1 cm$

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