A particle of mass 0.50 kg executes simple harmonic motion under force . The time period of oscillation is . The value of is

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Solution

Q.
A particle of mass 0.50 kg executes simple harmonic motion under force $F = - 50 (N m^{- 1}) x$ . The time period of oscillation is $\frac{x}{35} s$ . The value of $x$ is _______ $(G i v e n π = \frac{22}{7})$ [2024]

Ans.
(22) Time period $T = 2 π \sqrt{\frac{m}{k}} = 2 \times \frac{22}{7} \times \sqrt{\frac{0.50}{50}} = \frac{22}{35} s$

On comparing $\frac{x}{35} = \frac{22}{35} \Rightarrow x = 22$

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