A simple harmonic oscillator has an amplitude AAA and time period 6?6\pi6? seconds. Assuming the oscillation starts from its mean position, the time required by it to travel from to will be where

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
A simple harmonic oscillator has an amplitude A and time period $6 π$ seconds. Assuming the oscillation starts from its mean position, the time required by it to travel from $x = A$ to $x = \frac{\sqrt{3}}{2} A$ will be $\frac{π}{x} s,$ where $x =$ _________ . [2024]

Ans.
(2)

From phasor diagram particle has to move from P to Q in a circle of radius equal to the amplitude of SHM.

$\cos ϕ = \frac{\frac{\sqrt{3} A}{2}}{A} = \frac{\sqrt{3}}{2} \Rightarrow ϕ = \frac{π}{6}$

$Now, \frac{π}{6} = ω t = \frac{2 π}{T} t$

Want Us to Email you About Special Offers & Updates?