A metal block of mass is suspended from a rigid support through a metal wire of diameter 14 mm. The tensile stress developed in the wire under equilibrium state is . The value of mass is ________ kg. (Take, and ) [2023]

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Solution

Q.
A metal block of mass $m$ is suspended from a rigid support through a metal wire of diameter 14 mm. The tensile stress developed in the wire under equilibrium state is $7 \times 10^{5} {Nm}^{- 2}$ . The value of mass $m$ is ________ kg. (Take, $g = 9.8 {ms}^{- 2}$ and $π = \frac{22}{7}$ ) [2023]

Ans.
(11)

$Tensile stress, σ = \frac{F}{A} = \frac{4 m g}{π D^{2}}$

$∴$ $m = \frac{π D^{2} σ}{4 g}$

$= \frac{22}{7} \times \frac{{(14 \times 10^{- 3})}^{2} \times 7 \times 10^{5}}{4 \times 9.8} = 11 kg$

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