Two wires as shown in the figure below, are made of steel and have breaking stress of . Area of cross-section of upper

Question

Two wires as shown in the figure below, are made of steel and have breaking stress of $12 \times 10^{8} N / m^{2}$ . Area of cross-section of upper wire is $0.008 {cm}^{2}$ and of lower wire is $0.004 {cm}^{2}$ . The maximum mass that can be added to pan without breaking any wire is _______ kg. $(take g = 10 m / s^{2})$ [2026]

Smart Achievers · Accepted Answer

(2)

$T_{1} = m g$

$T_{2} = (10 + m) g$

$T_{3} = (30 + 10 + m) g = g (40 + m) g$

$Stress in upper wire$

$σ_{1} = \frac{(40 + m) g}{0.008 {cm}^{2}} = \frac{(40 + m) \times 10}{8 \times 10^{- 7}} N / m^{2}$

$Stress in lower wire$

$σ_{2} = \frac{(10 + m) g}{0.004 {cm}^{2}} = \frac{(10 + m) \times 10}{4 \times 10^{- 7}} N / m^{2}$

$Upper wire breaks:$

$\frac{(40 + m) \times 10}{8 \times 10^{- 7}} = 12 \times 10^{8}$

$So, maximum mass, without breaking any wire is 38 kg$

Solution

1 56

2 38

3 96

4 5.6

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