A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50 °C. The gas is now heated to double its temperature. The modified pressure is ____ Pa. [2026]

Question

A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50 °C. The gas is now heated to double its temperature. The modified pressure is ____ Pa. [2026]

Smart Achievers · Accepted Answer

(3730)

$As per NTA$

$V = constant$

$so P \propto T$

$T_{i} = 50 ° C = 323 K$

$T_{f} = 100 ° C = 373 K$

$\Rightarrow \frac{P_{f}}{P_{i}} = \frac{T_{f}}{T_{i}}$

$\Rightarrow \frac{P_{f}}{3.23 kPa} = \frac{373}{323}$

$\Rightarrow P_{f} = 3730 Pa$

$Other Solution:$

$As volume is constant$

$∴$ $P \propto T$

$Since T is doubled (must be in Kelvin),$ $so pressure$ $must be doubled$

$∴$ $P_{f} = 2 P_{i}$

$P_{f} = 2 \times 3.23 = 6.46 kPa$

$P_{f} = 6460 Pa$

Solution

Q.
A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50 °C. The gas is now heated to double its temperature. The modified pressure is ____ Pa. [2026]

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Solution

Q. A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50 °C. The gas is now heated to double its temperature. The modified pressure is ____ Pa. [2026]

Ans. (3730) As per NTA V=constant so P∝T Ti=50°C=323 K Tf=100°C=373 K ⇒PfPi=TfTi ⇒Pf3.23 kPa=373323 ⇒Pf=3730 Pa Other Solution: As volume is constant ∴ P∝T Since T is doubled (must be in Kelvin),so pressure must be doubled ∴ Pf=2Pi Pf=2×3.23=6.46 kPa Pf=6460 Pa

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Q.
A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50 °C. The gas is now heated to double its temperature. The modified pressure is ____ Pa. [2026]