Q.

One mole of an ideal gas passes through a process where pressure and volume obey the pressure P=P0[1-12(V0V)2]. Here P0 and V0 are constants. Calculate the change in the temperature of the gas, if its volume changes from V0 to 2V0.

1 12P0V0R  
2 54P0V0R  
3 34P0V0R  
4 14P0V0R  

Ans.

(2)

We have given,      P=P0[1+12(V0V)2]

When  V1=V0⇒P1=P0[1-12]=P02

When V2=2V0

ΔT=|(1nR)(P1V1-P2V2)|=(1nR)|(P0V02-7P0V04)|=5P0V04nR=5P0V04R    (∵n=1)