A galvanometer of resistance when connected in series with measures a voltage of up to 10 V. The value of resistance required to convert the galvanometer into an ammeter to read up to 10 A is . The value of is

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Solution

Q.
A galvanometer of resistance $100 Ω$ when connected in series with $400 Ω$ measures a voltage of up to 10 V. The value of resistance required to convert the galvanometer into an ammeter to read up to 10 A is $x \times 10^{- 2} Ω$ . The value of $x$ is [2024]

1 800

2 2

3 20

4 200

Ans.
(3)

For voltmeter,

$i_{g} = \frac{10}{400 + 100} = 20 \times 10^{- 3} A$

for ammeter

For ammeter

Let shunt resistance $= S$

$i_{g} R = (i - i_{g}) S$

$20 \times 10^{- 3} \times 100 = 10 S \Rightarrow S = 20 \times 10^{- 2} Ω$

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