In an ammeter, 5% of the main current passes through the galvanometer. If resistance of the galvanometer is G, the resistance of ammeter will be

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Solution

Q.
In an ammeter, 5% of the main current passes through the galvanometer. If resistance of the galvanometer is G, the resistance of ammeter will be [2024]

1 $\frac{G}{20}$

2 $\frac{G}{199}$

3 $199$ $G$

4 $200$ $G$

Ans.
(1)

By using KVL

$I_{g} \cdot G = I_{S} \cdot S$

$S = \frac{I_{g} G}{I_{S}} = \frac{\frac{5}{100} I_{0}}{\frac{95}{100} I_{0}} G = \frac{1}{19} G$

$R_{A} = \frac{S G}{S + G} = \frac{\frac{G}{19} \cdot G}{\frac{G}{19} + G} = \frac{G^{2}}{\frac{19 \times 20 G}{19}} = \frac{G}{20}$

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