A car P travelling at sounds its horn at a frequency of 400 Hz. Another car Q is travelling behind the first car in the same direction with a velocity . [2023]

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Solution

Q.
A car P travelling at $20 {ms}^{- 1}$ sounds its horn at a frequency of 400 Hz. Another car Q is travelling behind the first car in the same direction with a velocity $40 {ms}^{- 1}$ . The frequency heard by the passenger of the car Q is approximately (Take, velocity of sound $= 360 {ms}^{- 1}$ ) [2023]

1 514 Hz

2 421 Hz

3 485 Hz

4 471 Hz

Ans.
(2)

$f = f_{0} (\frac{c + v_{o}}{c + v_{s}})$

$f = 400 (\frac{360 + 40}{360 + 20})$

$\Rightarrow f = 421 Hz$

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