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Solution


Q.

A train blowing a whistle of frequency 320 Hz approaches an observer standing on the platform at a speed of 66 m/s. The frequency observed by the observer will be (given speed of sound = 330 ms-1) ________ Hz.              [2023]

Ans.

(400)

fapp=f(vv-vs)=320(330330-66)=400 Hz