A bird is flying at the height of 12 cm from the surface of a lake and a fish is swimming at a depth of 24 cm from the surface

Question

A bird is flying at the height of 12 cm from the surface of a lake and a fish is swimming at a depth of 24 cm from the surface.

(Take $μ = \frac{4}{3}$ )

	Column-A		Column-B
(A)	Distance of fish from the surface as seen by bird	(P)	16 cm
(B)	Distance of bird from the surface as seen by fish	(Q)	40 cm
(C)	Distance between fish and bird as seen by bird	(R)	18 cm
(D)	Distance between fish and bird as seen by fish	(S)	30 cm

Smart Achievers · Accepted Answer

(3)

$μ = \frac{4}{3}$

$R_{\max}^{2} - 4 (\frac{g R_{\max}^{2}}{2 v^{2}}) (H - \frac{g R_{\max}^{2}}{2 v^{2}}) = 0$

$0 = \frac{v^{2}}{2 g} + H - \frac{g R_{\max}^{2}}{2 v^{2}}$

$R_{\max} = \frac{v}{g} \sqrt{v^{2} + 2 g H}$

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