Q 11 :    

A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy ΔU of the gas in joules will be               [2017]
 

  • −500 J

     

  • −505 J

     

  • +505 J

     

  • 1136.25 J

     

(2)

w=-PextΔV=-2.5(4.50-2.50)

=-5L atm=-5×101.325J=-506.625 J

ΔU=q+w

As the container is insulated, thus q=0

Hence, ΔU=w=-506.625 J