Q 1 :    

Choose the correct statement for the work done in the expansion and heat absorbed or released when 5 litres of an ideal gas at 10 atmospheric pressure isothermally expands into vacuum until volume is 15 litres.                 [2024]

  • both the heat and work done will be greater than zero.

     

  • heat absorbed will be less than zero and work done will be positive.

     

  • work done will be zero and heat will also be zero.

     

  • work done will be greater than zero and heat will remain zero.

     

(3)

 



Q 2 :    

For the following reaction at 300 K,

A2(g)+3B2(g)2AB3(g)

The enthalpy change is +15kJ, then the internal energy change is:             [2024]

  • 19988.4 J

     

  • 200 J

     

  • 1999 J

     

  • 1.9988 kJ

     

(1)

If np<nr and Δng=np-nr=-ve; then,

ΔH<ΔE  

As ΔH=+15kJ or +15,000J, the only possible answer from the given options is 19988.4 J.



Q 3 :    

The work done during reversible isothermal expansion of one mole of hydrogen gas at 25°C from pressure of 20 atmosphere to 10 atmosphere is:
(Given R=2.0 cal K-1mol-1)                     [2024]

  • 0 calorie

     

  • –413.14 calories

     

  • 413.14 calories

     

  • 100 calories

     

(2)

w=-2.303nRTlogV2V1

or w=-2.303nRTlogP1P2

=-2.303×1×2×298×log2010=-413.14 calories



Q 4 :    

Which amongst the following options is the correct relation between change in enthalpy and change in internal energy?           [2023]

  • ΔH-ΔU=-ΔnRT

     

  • ΔH+ΔU=ΔnR

     

  • ΔH=ΔU-ΔngRT

     

  • ΔH=ΔU+ΔngRT

     

(4)

ΔH=ΔU+ΔngRT



Q 5 :    

Which of the following P–V curve represents maximum work done?         [2022]

  • [MAGE 31]

     

  • [MAGE 32]

     

  • [MAGE 33]

     

  • [MAGE 34]

     

(2)

 



Q 6 :    

Which one among the following is the correct option for right relationship between CP and CV for one mole of ideal gas?       [2021]

  • CV=RCP

     

  • CP+CV=R

     

  • CP-CV=R

     

  • CP=RCV

     

(3)

CP=CV+nR

For one mole of ideal gas,

CP=CV+R  or  CP-CV=R



Q 7 :    

The correct option for free expansion of an ideal gas under adiabatic condition is           [2020]

  • q=0, ΔT=0 and w=0

     

  • q=0, ΔT<0 and w>0

     

  • q<0, ΔT=0 and w=0

     

  • q>0, ΔT>0 and w>0

     

(1)

For free expansion of an ideal gas, Pex=0,

w=-PexΔV=0

For adiabatic process, q=0

According to the first law of thermodynamics,

ΔU=q+w

As internal energy of an ideal gas is a function of temperature,

ΔU=0,    ΔT=0



Q 8 :    

Under isothermal conditions, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]           [2019]

  • 30 J

     

  • -30 J

     

  • 5 kJ

     

  • 25 J  

     

(2)

Expansion of a gas against a constant external pressure is an irreversible process. The work done in an irreversible process

=-PextΔV=-Pext(V2-V1)=-2(0.25-0.1)

=-2×0.15L bar=-0.30×100J=-30J



Q 9 :    

Reversible expansion of an ideal gas under isothermal and adiabatic conditions are as shown in the figure.        

[IMAGE 35]
AB Isothermal expansion
AC Adiabatic expansion
Which of the following options is not correct?                                      [2019]

  • ΔSisothermal>ΔSadiabatic

     

  • TA=TB

     

  • Wisothermal>Wadiabatic

     

  • TC>TA

     

(4)

For an ideal gas, internal energy is a function of temperature. Final temperature i.e., TC for adiabatic process is less than its initial temperature i.e., TA
  TC<TA



Q 10 :    

An ideal gas expands isothermally from 10-3m3 to 10-2m3 at 300 K against a constant pressure of 105N m-2. The work done on the gas is    [2019]
 

  • +270 kJ

     

  • -900 J

     

  • +900 kJ

     

  • -900 kJ

     

(2)

w=-PdV=-P(V2-V1)

=-105Nm-2(10-2-10-3)m3=-105Nm-2(9×10-3)m3

=-9×102Nm=-900J                                         (1J=1Nm)