Q 1 :

Ice at –5°C is heated to become vapor with temperature of 110°C at atmosphere pressure. The entropy change associated with this process can be obtained from    [2025]

  • ∫268K273KCp,m dT+ΔHm,fusionTf+ΔHm,vaporisationTb+∫273K373KCp,m dT+∫373K383KCp,m dT

     

  • ∫268K383KCp dT+ΔHmelting273+ΔHboiling373

     

  • ∫268K273KCp,mT dT+ΔHm,fusionTf+ΔHm,vaporisationTb+∫273K373KCp,mdTT +∫373K383KCp,mdTT 

     

  • ∫268K383KCp dT+qrevT

     

(3)

Ice(-5°C)→∫268273Cp,mdTT Ice(-0°C)→ΔHm(fusion)Tf Water (-0°C)→∫273373Cp,mdTT Water(100°C)→ΔHm(vap)Tb Water (-0°C)→∫273373Cp,mdTT Water(100°C)

 



Q 2 :

One mole of an ideal gas at 350 K is in a 2.0 L vessel of thermally conducting walls, which are in contact with the surroundings. It undergoes isothermal reversible expansion from 2.0 L to 3.0 L against a constant pressure of 4 atm. The change in entropy of the surroundings (ΔS) is ______ JK-1 (Nearest integer) Given: R = 8.314 J K-1 mol-1      [2023]



(3)

Δsystem=nR ln(V2V1)

              =1×8.314 ln(32)

Δsystem=3.37

Δsurr=3.37≈3



Q 3 :

30.4 kJ of heat is required to melt one mole of sodium chloride and the entropy change at the melting point is 28.4 J K-1 mol-1 at 1 atm. The melting point of sodium chloride is ________ K. (Nearest integer)            [2023]



(1070)

ΔS=ΔHfusTmp

28.4=30.4×1000Tmp

Tmp=1070.422 K



Q 4 :

Which of the following reaction(s) has a positive entropy change?

I)  Ag+(aq)+Cl-(aq)→AgCl(s)

II)  NH4Cl(s)→NH3(g)+HCl(g)

III)  2NH3(g)→N2(g)+3H2(g)

  • I and II 

     

  • III only

     

  • II & III 

     

  • II only

     

(3)

In (I), solid formed. In others more number of moles of gases are formed, ΔS=+ve

 



Q 5 :

Consider the expansion of one mole of an ideal gas from an initial state to a final state, with ΔS representing the entropy change in the process. The correct statement is:

  • If the process is carried out reversibly, the value of ΔS will be higher in comparison to its irreversible counterpart.

     

  • If the process is adiabatic, the value of ΔS is always zero, irrespective of whether the process is carried out reversibly or irreversibly.

     

  • If the process is isothermal, there will not be any heat exchange with the surrounding since the temperatures of the system and the surrounding are equal.

     

  • If the process is isothermal and the final volume is double of the initial volume, the value of ΔS will be independent of the temperature.

     

(4)

For isothermal, ΔSsys=nRln(VfVi)