Q 1 :    

Ice at –5°C is heated to become vapor with temperature of 110°C at atmosphere pressure. The entropy change associated with this process can be obtained from    [2025]

  • 268K273KCp,mdT+ΔHm,fusionTf+ΔHm,vaporisationTb+273K373KCp,mdT+373K383KCp,mdT

     

  • 268K383KCpdT+ΔHmelting273+ΔHboiling373

     

  • 268K273KCp,mTdT+ΔHm,fusionTf+ΔHm,vaporisationTb+273K373KCp,mdTT+373K383KCp,mdTT

     

  • 268K383KCpdT+qrevT

     

(3)

Ice(-5°C)268273Cp,mdTTIce(-0°C)ΔHm(fusion)Tf Water (-0°C)273373Cp,mdTTWater(100°C)ΔHm(vap)Tb Water (-0°C)273373Cp,mdTTWater(100°C)