Q 1 :    

Which of the following is not correct?            [2024]

  • G is zero for a reversible reaction.

     

  • G is negative for a spontaneous reaction.

     

  • G is positive for a spontaneous reaction.

     

  • G is positive for a non-spontaneous reaction.

     

(C)            G=0reaction at equilibrium

                  G>0non spontaneous reaction

                  G<0spontaneous reaction

 



Q 2 :    

Consider the following reaction at 298 K. 32O2(g)O3(g)Kp=2.47×10-29,ΔrGΘ for the reaction is __________ kJ.

 

(Given R=8.314 JK-1 mol-1)                   [2024]



(163)

log(K)=log10(2.47×10-29)log10(25×10-30)

           =log10(52×10-30)=2log105-30 log 10

                                                =2×0.7-30×1=-28.6

ΔG°=-2.303 RT log10K

ΔG°=-2.303×8.314JK mol×298K×log10(2.47×10-29)

         =-2.303×8.314×298×(-28.6)J mol-1=163.2kJmol-1

 



Q 3 :    

For the reaction at 298 K, 2A + BC. H = 400 kJ mol-1 and S = 0.2 kJ mol-1 K-1. The reaction will become spontaneous above ________ K.         [2024]



(2000)

For reaction to be spontaneous,

ΔG<0

ΔH-TΔS<0

400kJ mol-1-T×0.2kJ mol-1K-1<0

400kJ mol-1<T×0.2kJ mol-1K-1

T>4000.2K

T>2000K

 



Q 4 :    

When ΔHvap=30kJ/mol and Svap=75J mol-1 K-1, then the temperature of vapour, at one atmosphere is ___________ K.      [2024]



(400) 

When external pressure is 1 atm ,then vapours are formed at normal boiling point of the liquid. So in the question, normal boiling point of the liquid is asked.

ΔSvap=ΔHvapTbpt

75J mol-1K-1=30×1000Jmol-1Tbpt

Tbpt=400K