Ice at –5°C is heated to become vapor with temperature of 110°C at atmosphere pressure. The entropy change associated with this process can be obtained from [2025]

Question

Ice at –5°C is heated to become vapor with temperature of 110°C at atmosphere pressure. The entropy change associated with this process can be obtained from [2025]

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$Ice (- 5^{°} C)$ $\overset{\int_{268}^{273} \frac{C_{p, m} d T}{T}}{\to}$ $Ice (- 0^{°} C)$ $\overset{\frac{Δ H_{m} (fusion)}{T_{f}}}{\to}$ $Water (- 0^{°} C)$ $\overset{\int_{273}^{373} \frac{C_{p, m} d T}{T}}{\to}$ $Water (100^{°} C)$ $\overset{\frac{Δ H_{m} (vap)}{T_{b}}}{\to}$ $Water (- 0^{°} C)$ $\overset{\int_{273}^{373} \frac{C_{p, m} d T}{T}}{\to}$ $Water (100^{°} C)$

Solution

Q.
Ice at –5°C is heated to become vapor with temperature of 110°C at atmosphere pressure. The entropy change associated with this process can be obtained from [2025]

1 $\int_{268 K}^{273 K} C_{p, m} d T + \frac{Δ H_{m, fusion}}{T_{f}} + \frac{Δ H_{m, vaporisation}}{T_{b}} + \int_{273 K}^{373 K} C_{p, m} d T + \int_{373 K}^{383 K} C_{p, m} d T$

2 $\int_{268 K}^{383 K} C_{p} d T + \frac{Δ H_{melting}}{273} + \frac{Δ H_{boiling}}{373}$

3 $\int_{268 K}^{273 K} \frac{C_{p, m}}{T} d T + \frac{Δ H_{m, fusion}}{T_{f}} + \frac{Δ H_{m, vaporisation}}{T_{b}} + \int_{273 K}^{373 K} \frac{C_{p, m} d T}{T} + \int_{373 K}^{383 K} \frac{C_{p, m} d T}{T}$

4 $\int_{268 K}^{383 K} C_{p} d T + \frac{q_{rev}}{T}$

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Solution

Q. Ice at –5°C is heated to become vapor with temperature of 110°C at atmosphere pressure. The entropy change associated with this process can be obtained from [2025]

1 ∫268K273KCp,m dT+ΔHm,fusionTf+ΔHm,vaporisationTb+∫273K373KCp,m dT+∫373K383KCp,m dT

2 ∫268K383KCp dT+ΔHmelting273+ΔHboiling373

3 ∫268K273KCp,mT dT+ΔHm,fusionTf+ΔHm,vaporisationTb+∫273K373KCp,mdTT +∫373K383KCp,mdTT

4 ∫268K383KCp dT+qrevT