Q 1 :    

Three identical heat conducting rods are connected in series as shown in the figure. The rods on the sides have thermal conductivity 2 K while that in the middle has thermal conductivity K. The left end of the combination is maintained at temperature 3T and the right end at T. The rods are thermally insulated from outside. In steady state, temperature at the left junction is T1 and that at the right junction is T2. The ratio T1T2 is               [2025]

[IMAGE 98]
 

  • 53

     

  • 54

     

  • 32

     

  • 43

     

(1)

[IMAGE 99]

According to heat transfer, at junction T1

2KA(3T-T1)L=KA(T1-T2)L

Since all identical rods are connected in series,

So, A and L are same.

    6T-2T1=T1-T2

6T=3T1-T2                                  ...(i)

At junction T2,

KA(T1-T2)L=2KA(T2-T)L

or    T1-T2=2T2-2T

or    2T=3T2-T1                                  ...(ii)

From eqn. (i) and (ii),

T1T2=53



Q 2 :    

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Houses made of concrete roofs overlaid with foam keep the room hotter during summer.
Reason R: The layer of foam insulation prohibits heat transfer, as it contains air pockets.
In the light of the above statements, choose the most appropriate answer from the options given below:          [2024]

  • A is true but R is false.

     

  • A is false but R is true.

     

  • Both A and R are true and R is the correct explanation of A.

     

  • Both A and R are true but R is not the correct explanation of A.

     

(2)

Houses made of concrete roofs generally keep the room hotter during summer, but the roofs overlaid with foam make the room cooler. As this layer of foam prohibits heat transfer as it contains air pockets. So, assertion is false but reason is true.

 



Q 3 :    

The mechanical quantity, which has dimensions of reciprocal of mass M-1 is                      [2023]

  • angular momentum

     

  • coefficient of thermal conductivity

     

  • torque

     

  • gravitational constant

     

(4)

Angular momentum, L=[ML2T-1]

Coefficient of thermal conductivity, K=[MLT-3K-1]

Gravitational constant, G=[M-1L-3T-2]

So, gravitational constant has dimensions of reciprocal of mass.



Q 4 :    

The energy that will be ideally radiated by a 100 kW transmitter in 1 hour is           [2022]
 

  • 36×107 J

     

  • 36×104 J

     

  • 36×105 J

     

  • 1×105 J

     

(1)

Power, P=100KW=100×103W

Time, t=1 hr=3600 s

Energy, E=power×time

E=100×103×3600

E=36×107J



Q 5 :    

The power radiated by a black body is P and it radiates maximum energy at wavelength, λ0. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 34λ0, the power radiated by it becomes nP. The value of n is                  [2018]
 

  • 34

     

  • 43

     

  • 25681

     

  • 81256

     

(3)

From Wien’s law, λmaxT=constant

So, λmax1T1=λmax2T2

λ0T=3λ04T'T'T=43

According to Stefan–Boltzmann law, energy emitted per unit time by a black body is AeσT4, i.e., power radiated.

    PT4

So,  P'P=(T'T)4n=(43)4=25681



Q 6 :    

Two rods A and B of different materials are welded together as shown in figure. Their thermal conductivities are K1 and K2. The thermal conductivity of the composite rod will be        [2017]

[IMAGE 100]
 

  • 3(K1+K2)2

     

  • K1+K2

     

  • 2(K1+K2)

     

  • K1+K22

     

(4)

Equivalent thermal conductivity of the composite rod in parallel combination will be,

K=K1A1+K2A2A1+A2=K1+K22



Q 7 :    

A spherical black body with a radius of 12 cm radiates 450 watt power at 500 K. If the radius were halved and the temperature doubled, the power radiated in watt would be   [2017]

  • 450

     

  • 1000

     

  • 1800

     

  • 225

     

(3)

According to Stefan-Boltzmann law, rate of energy radiated by a black body is given as

        E=σAT4=σ4πR2T4

Given E1=450W,  T1=500K,  R1=12cm

         R2=R12,  T2=2T1,  E2=?

E2E1=σ4πR22T24σ4πR12T14=(R2R1)2(T2T1)4E2E1=14×16=4

        E2=E1×4=450×4=1800 W

 



Q 8 :    

A black body is at a temperature of 5760 K. The energy of radiation emitted by the body at wavelength 250 nm is U1, at wavelength 500 nm is U2 and that at 1000 nm is U3. Wien’s constant, b=2.88×106nm K. Which of the following is correct?           [2016]
 

  • U1>U2

     

  • U2>U1

     

  • U1=0

     

  • U3=0

     

(2)

According to Wien's displacement law 

λm=bT=2.88×106nm K5760K=500 nm

[IMAGE 101]

Clearly from graph U2>U3 and U2>U1



Q 9 :    

The two ends of a metal rod are maintained at temperatures 100°C and 110°C. The rate of heat flow in the rod is found to be 4.0J/s. If the ends are maintained at temperatures 200°C and 210°C, the rate of heat flow will be              [2015]
 

  • 8.0 J/s

     

  • 4.0 J/s

     

  • 44.0 J/s

     

  • 16.8 J/s

     

(2)