Q 21 :

A child stands on the edge of the cliff 10 m above the ground and throws a stone horizontally with an initial speed of 5 ms-1. Neglecting the air resistance, the speed with which the stone hits the ground will be ______ ms-1 (given, g = 10 ms-2).                  [2023]

  • 20

     

  • 15

     

  • 30

     

  • 25

     

(2)

vy=2gh=200

vnet=25×200=15 m/s



Q 22 :

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: When a body is projected at an angle 45°, its range is maximum.

Reason R: For maximum range, the value of sin 2θ should be equal to one.

In the light of the above statements, choose the correct answer from the options given below:             [2023]

  • Both A and R are correct but R is NOT the correct explanation of A

     

  • Both A and R are correct and R is the correct explanation of A

     

  • A is false but R is true

     

  • A is true but R is false

     

(2)

R=u2gsin2θ

R is maximum for 2θ=90°



Q 23 :

Two projectiles A and B are thrown with initial velocities of 40 m/s and 60 m/s at angles 30° and 60° with the horizontal respectively. The ratio of their ranges respectively is(g=10m/s2)         [2023]

  • 1 : 1

     

  • 4 : 9

     

  • 2 : 3

     

  • 3 : 2

     

(2)

R1=u12sin2θ1g,  R2=u22sin2θ2g

R1R2=u12sin2θ1u22sin2θ2=402sin(2×30°)602sin(2×60°)=49



Q 24 :

The trajectory of a projectile, projected from the ground, is given by y=x-x220, where x and y are measured in meter. The maximum height attained by the projectile will be.             [2023]

  • 102 m

     

  • 200 m

     

  • 10 m

     

  • 5 m

     

(4)

y=x-x220

For maximum height,  dydx=01-2x20=0

x=10

So, ymax=10-10020=5 m



Q 25 :

The range of the projectile projected at an angle of 15° with the horizontal is 50 m. If the projectile is projected with the same velocity at an angle of 45° with the horizontal, then its range will be                 [2023]

  • 50 m

     

  • 502 m

     

  • 100 m

     

  • 1002 m

     

(3)

R=v2sin2θg

Rsin(2θ)

R1R2=sin(2θ1)sin(2θ2)=sin(2×15°)sin(2×45°)=sin30°sin90°

50R2=12

R2=100 m



Q 26 :

Two projectiles are projected at 30° and 60° with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is      [2023]

  • 2 : 3

     

  • 3 : 1

     

  • 1 : 3

     

  • 1 : 3

     

(3)

Hmax=u2sin2θ2g

H1H2=sin2θ1sin2θ2=13



Q 27 :

A projectile is projected at 30° from the horizontal with initial velocity 40m s-1. The velocity of the projectile at t=2 s from the start will be (Given g=10m/s2)           [2023]

  • 203 ms-1

     

  • 403 ms-1

     

  • 20 ms-1

     

  • zero

     

(1)

At t=2 particle is at maximum height moving with velocity v=40cos30°=203 ms-1



Q 28 :

Two bodies are projected from ground with same speeds 40 m s-1 at two different angles with respect to horizontal. The bodies were found to have same range. If one of the body was projected at an angle of 60° with horizontal then sum of the maximum heights, attained by the two projectiles, is ______ m. (Given g = 10 m s-2)        [2023]



(80)

Since range is same

θ1+θ2=90°

θ2=30°

(Hmax)1+(Hmax)2=U2sin2θ12g+U2sin2θ22g

=40220(14+34)=80 m



Q 29 :

A projectile fired at 30° to the ground is observed to be at same height at time 3 s and 5 s after projection, during its flight. The speed of projection of the projectile is ______ m s-1 (Given g = 10 m s-2)              [2023]



(80)

Time of flight  t1+t2=3+5=8 sec

T=2usin30°g

8=2usin(30°)10

u=80 m/s



Q 30 :

A boy throws a ball into air at 45° from the horizontal to land it on a roof of a building of height H. If the ball attains maximum height in 2 s and lands on the building in 3 s after launch, then the value of H is _______ m.    (g=10m/s2)                                                 [2026]

  • 25

     

  • 15

     

  • 20

     

  • 10

     

(2)