All the letters of the word “GTWENTY” are written in all possible ways with or without meaning and these words are written as in a dictionary. The serial number of the word “GTWENTY” is _____. [2024]
(553)
Number of words starts with
Number of words starts with
Number of words starts with
Number of words starts with
Number of words starts with
Number of words starts with
Next word will be GTWENTY
Rank of GTWENTY
The largest such that divides is : [2025]
23
22
21
20
(2)
The number of times a prime p divides is
Required largest value of
= 16 + 5 + 1 = 22
Hence, the maximum value of is 22.
The number of sequences of ten terms, whose terms are either 0 or 1 or 2, that contain exactly five 1s and exactly three 2s, is equal to : [2025]
360
1820
45
2520
(4)
Given number in the sequences are 11111 222 00
Number of sequences = = 2520
In a group of 3 girls and 4 boys, there are two boys and . The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but and are not adjacent to each other, is : [2025]
144
120
96
72
(1)
Total number of ways
The Number of words, which can be formed using all the letters of the word "DAUGHTER", so that all the vowels never come together, is [2025]
34000
36000
37000
35000
(2)
Number of words in which vowels never come together
= Total number of words – Number of words in which vowels come together
= 36000
The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, such that the sum of their first and last digits should not be more than 8, is [2025]
4608
4607
5719
5720
(2)
Given digits are 0, 1, 2, 3, 4, 5, 6, 7.
First place can be filled in 3ways, i.e., (5, 6, 7)
For place as 5, last place can be 0, 1, 2, 3
Total number of ways = = 2048
For place as 6, last place can be 0, 1, 2
Total number of ways = = 1536
For place as 7, last place can be 0, 1
Total number of ways = = 1024
Total number of ways = 2048 + 1536 + 1024 = 4608
So, 50000 is not included i.e., 4608 – 1 = 4607
Let P be the set of seven digit numbers with sum of their digits equal to 11. If the numbers in P are formed by using the digits 1, 2 and 3 only, then the number of elements in the set P is : [2025]
158
164
173
161
(4)
(i) Number of numbers formed using 1 and 3, i.e.,
(ii) Number of numbers formed using 1, 2, 3 i.e.,
(iii) Number of numbers formed using 1 and 2, i.e.,
Number of elements in set P = 161.
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at position in this arrangement, is : [2025]
PRNAUK
PRKANU
PRKAUN
PRNAKU
(3)
We have, A, K, N, P, R, U
Now, to calculate rank
Number of words start with A = 5! = 120
Number of words starts with K = 5! = 120
Number of words starts with N = 5! = 120
Number of words starts with PA = 4! = 24
Number of words starts with PK = 4! = 24
Number of words starts with PN = 4! = 24
Number of words starts with PRA = 3! = 6
Number of words starts with PRKANU = 1
Number of words starts with PRKAUN = 1
words is PRKAUN.
If the number of seven-digit numbers, such that the sum of their digits is even, is , then m + n is equal to __________. [2025]
(14)
Total 7 digit numbers = 9000000
7 digit numbers having sum of their digits is even
On comparing with , we get
m = 9 and n = 5
m + n = 14.
Let m and n, (m < n), be two 2-digit numbers. Then the total numbers of pairs (m, n), such that gcd (m, n) = 6, is __________. [2025]
(64)
Given m and n are 2-digit numbers (m < n).
Such that gcd (m, n) = 6.
Let m = 6a, n = 6b, where a and b are coprime integers a < b.
.
.
Now, if a = 2, then b = 3, 5, 7, 9, 11, 13, 15 = 7
a = 3, then b = 4, 5, 7, 8, 10, 11, 13, 14, 16 = 9
a = 4, then b = 5, 7, 9, 11, 13, 15 = 6
a = 5, then b = 6, 7, 8, 9, 11, 12, 13, 14, 16 = 9
a = 6, then b = 7, 11, 13 = 3
a = 7, then b = 8, 9, 10, 11, 12, 13, 15, 16 = 8
a = 8, then b = 9, 11, 13, 15 = 4
a = 9, then b = 10, 11, 13, 14, 16 = 5
a = 10, then b = 11, 13 = 2
a = 11, then b = 12, 13, 14, 15, 16 = 5
a = 12, then b = 13 = 1
a = 13, then b = 14, 15, 16 = 3
a = 14, then b = 15 = 1
a = 15, then b = 16 = 1
Total possible number of ordered pairs = 64.