In a group of 3 girls and 4 boys, there are two boys and . The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but and are not adjacent to each other, is :

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Solution

Q.
In a group of 3 girls and 4 boys, there are two boys $B_{1}$ and $B_{2}$ . The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but $B_{1}$ and $B_{2}$ are not adjacent to each other, is : [2025]

1 144

2 120

3 96

4 72

Ans.
(1)

Total number of ways

$= 3! \times 4! \times 2! - 3! \times 3! \times 2! \times 2! = 144$

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