If limx→0e(a-1)x+2cosbx+(c-2)e-xxcosx-loge(1+x)=2, then a2+b2+c2 is equal to: [2026]
7
3
5
9
(1)
The value of limx→0loge (sec(ex)·sec (e2x)⋯sec (e10x))e2-e2cosx is equal to [2026]
(e10-1)2e2e2-1
(e20-1)2e2e2-1
(e10-1)2e2-1
(e20-1)2e2-1
(4)