Q 1 :

A planet of radius R=110×(radius of Earth) has the same mass density as Earth. Scientists dig a well of depth R5 on it and lower a wire of the same length and a linear mass density 10-3 kg m-1 into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the radius of Earth =6×106 m and the acceleration due to gravity on Earth is 10 ms-2)                         [2014]

  • 96 N

     

  • 108 N

     

  • 120 N

     

  • 150 N

     

(2)

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The mass of the wire =10-3×1.2×105=120 kg

Acceleration due to gravity at the surface of the planet and earth

        gp=43πρGRp;   ge=43πρGRE

 gpge=RpRE=110  gp=1010=1 ms-2

Let gpM be the acceleration due to gravity at point M which is the midpoint of the wire and is at a depth of Rp10.

gpM=gp[1-Rp/10Rp]=1[1-0.1]=0.9 ms-2

 Force=mass of wire×gpM=120×0.9=108 N