Q 1 :    

Which one of the following factors will not affect the Hardy-Weinberg equilibrium?              [2024]

  • Genetic recombination

     

  • Genetic drift

     

  • Gene migration

     

  • Constant gene pool

     

(4)

Five factors are known to affect Hardy-Weinberg equilibrium. These are gene migration or gene flow, genetic drift, mutation, genetic recombination and natural selection.

 



Q 2 :    

Natural selection where more individual acquire specific character value other than the mean character value, leads to            [2022]

  • stabilising change

     

  • directional change

     

  • disruptive change

     

  • random change

     

(2)

 



Q 3 :    

The factor that leads to Founder effect in a population is                 [2021]

  • genetic drift

     

  • natural selection

     

  • genetic recombination

     

  • mutation

     

(1)

 



Q 4 :    

In a species, the weight of newborn ranges from 2 to 5 kg. 97% of the newborn with an average weight between 3 to 3.3 kg survive whereas 99% of the infants born with weights from 2 to 2.5 or 4.5 to 5 kg die. Which type of selection process is taking place?               [2019]

  • Cyclical selection

     

  • Directional selection

     

  • Stabilising selection

     

  • Disruptive selection

     

(3)

Stabilising selection is a balancing type of natural selection which favours average sized individuals and eliminates extreme individuals.

 



Q 5 :    

A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?                  [2019]

  • 0.16 (AA); 0.36 (Aa); 0.48 (aa)

     

  • 0.36 (AA); 0.48 (Aa); 0.16 (aa)

     

  • 0.16 (AA); 0.24 (Aa); 0.36 (aa)

     

  • 0.16 (AA); 0.48 (Aa); 0.36 (aa)

     

(4)

Frequency of dominant allele (A) = 0.4

Applying Hardy-Weinberg equilibrium; p+q=1

q=1-0.4=0.6;  p2+q2+2pq=1

Frequency of homozygous dominant genotype

(p2  AA)=(0.4)2=0.16

Frequency of heterozygous genotype

(2pq  Aa)=2×0.4×0.6=0.48

Frequency of homozygous recessive genotype

(q2  aa)=(0.6)2=0.36



Q 6 :    

Artificial selection to obtain cows yielding higher milk output represents            [2017]

  • directional as it pushes the mean of the character in one direction

     

  • disruptive as it splits the population into two, one yielding higher output and the other lower output

     

  • stabilising followed by disruptive as it stabilises the population to produce higher yielding cows

     

  • stabilising selection as it stabilises this character in the population

     

(1)

 



Q 7 :    

Genetic drift operates in                           [2016, 2002]

  • small isolated population

     

  • large isolated population

     

  • non-reproductive population

     

  • slow reproductive population

     

(1)

The random changes in gene frequencies in a population occurring by chance alone rather than by natural selection are called genetic drift or Sewall Wright effect. The effects of genetic drift are most marked in very small isolated population, although it occurs in all populations.

 



Q 8 :    

In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by             [2016]

  • p2

     

  • 2pq

     

  • pq

     

  • q2

     

(2)


In a stable population, for a gene with two alleles, ‘A’ (dominant) and ‘a’ (recessive), if the frequency of ‘A’ is p and the frequency of ‘a’ is q, then the frequencies of the three possible genotypes (AA, Aa and aa) can be expressed by the Hardy-Weinberg equation:

p2+2pq+q2=1

where 

      p2 = Frequency of AA (homozygous dominant) individuals

      q2 = Frequency of aa (homozygous recessive) individuals

      2pq = Frequency of Aa (heterozygous) individuals

 



Q 9 :    

In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is    [2014]

  • 0.4

     

  • 0.5

     

  • 0.6

     

  • 0.7

     

(3)

According to Hardy-Weinberg principle

       p2+2pq+q2=1;(p+q)2=1

      (AA)p2= 360 out of 1000 individuals

or   p2=0.36

Therefore, p=0.6