Electromagnetic Induction NEET Previous Year Questions with Answers

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Given, $n = 2 \times 10^{4},$ $I = 4$ $A$

Initially $I = 0$ $A$ $∴$ $B_{i} = 0$ or $ϕ_{i} = 0$

Finally, the magnetic field at the centre of the solenoid is given as

$B_{f} = μ_{0} n I = 4 π \times 10^{- 7} \times 2 \times 10^{4} \times 4 = 32 π \times 10^{- 3}$ $T$

Final magnetic flux through the coil is given as

$ϕ_{f} = N B A = 100 \times 32 π \times 10^{- 3} \times π \times {(0.01)}^{2}$

$ϕ_{f} = 32 π^{2} \times 10^{- 5} {Tm}^{2}$

Induced charge, $q = \frac{| Δ ϕ |}{R} = \frac{| ϕ_{f} - ϕ_{i} |}{R} = \frac{32 π^{2} \times 10^{- 5}}{10 π^{2}}$

$= 32 \times 10^{- 6} C = 32$ $μ C$

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