Q 21 :    

Pair of transition metal ions having the same number of unpaired electrons is :             [2025]
 

  • V2+,Co2+

     

  • Ti2+,Co2+

     

  • Fe3+,Cr2+

     

  • Ti3+,Mn2+

     

(1)

Ion Electronic configuration Number of unpaired electrons
V2+ [Ar]183d3 3
Co2+ [Ar]183d7
Ti2+ [Ar]183d2 2
Fe3+ [Ar]183d5 5
Cr2+ [Ar]183d4
Ti3+ [Ar]183d1 1
Mn2+ [Ar]183d5 5


Q 22 :    

The correct decreasing order of spin only magnetic moment values (B.M.) of Cu+, Cu2+, Cr2+ and Cr3+ ions is :       [2025]

  • Cu+>Cu2+>Cr3+>Cr2+

     

  • Cu2+>Cu+>Cr2+>Cr3+

     

  • Cr2+>Cr3+>Cu2+>Cu+

     

  • Cr3+>Cr2+>Cu+>Cu2+

     

(3)

Ion Electronic configuration Number of unpaired electrons (n) Spin only magnetic moment (μ)=n(n+2) BM
Cu+ [Ar]183d10 0 0
Cu2+ [Ar]183d9 1 1(1+2)BM=3BM
Cr2+  [Ar]183d4 4 4(4+2)BM=24BM
Cr3+ [Ar]183d3 3 3(3+2)BM=15BM

 

Thus, the decreasing order of spin-only magnetic moment is: Cr2+>Cr3+>Cu2+>Cu+
 

 



Q 23 :    

Match List I with List II.         [2025]

  List I   List II
  (Transition metal ion)   (Spin only magnetic moment (B.M.))
A. Ti3+ I. 3.87
B. V2+ II. 0.00
C. Ni2+ III. 1.73
D. Sc3+ IV. 2.84

 

Choose the correct answer from the options given below:

  • A–III, B–I, C–IV, D–II

     

  • A–III, B–I, C–II, D–IV

     

  • A–IV, B–II, C–III, D–I

     

  • A–II, B–IV, C–I, D–III

     

(1)

Transition metal ion Electronic configuration Number of unpaired electrons (n) Spin only magnetic moment (μ)=n(n+2)BM
Ti3+ [Ar]183d1 1 1(1+2)BM=1.73 BM
V2+ [Ar]183d3 3 3(3+2)BM=3.87 BM
Ni2+ [Ar]183d8 2 2(2+2)BM=2.83 BM 
Sc3+ [Ar]183d0 0 0(0+2)BM=0 BM

 



Q 24 :    

The correct option with order of melting points of the pairs (Mn, Fe), (Tc, Ru) and (Re, Os) is :   [2025]

  • Mn < Fe, Tc < Ru and Os < Re

     

  • Fe < Mn, Ru < Tc and Re < Os

     

  • Mn < Fe, Tc < Ru and Re < Os

     

  • Fe < Mn, Ru < Tc and Os < Re

     

(1)

In any row the melting points of these metals rise to a maximum at d5 except for anomalous values of Mn and Tc and fall regularly as the atomic number increases. The maxima at about the middle of each series indicate that one unpaired electron per d orbital is particularly favourable for strong interatomic interaction. In general, greater the number of valence electrons, stronger is the resultant bonding. Because of stable half filled configurations, Mn and Tc have lesser tendency to participate in metallic bonding, hence have lower melting points than expected value.

 



Q 25 :    

The element that does not belong to the same period of the remaining elements (modern periodic table) is :  [2025]

  • Platinum

     

  • Osmium

     

  • Palladium

     

  • Iridium

     

(3)

  GP-8 GP-9 GP-10
P-5     Pd
P-6 Os Ir Pt

 



Q 26 :    

The number of valence electrons present in the metal among Cr, Co, Fe and Ni which has the lowest enthalpy of atomisation is  [2025]

  • 8

     

  • 9

     

  • 1

     

  • 10

     

(3)

Element Cr Fe Co Ni
Ionization enthalpy (kJ/mol) 397 416 425 430

 

Cr has lowest enthalpy of atomization among given options.

Cr24=[Ar]183d54s1

Cr has 6 valence electrons.



Q 27 :    

The first transition series metal ‘M’ has the highest enthalpy of atomisation in its series. One of its aquated ions (Mn+) exists in green colour. The nature of the oxide formed by the above Mn- ion is :  [2025]

  • neutral 

     

  • acidic

     

  • basic

     

  • amphoteric

     

(3)

In first transition series (3d series) Vanadium has highest enthalpy of atomization. V3+ is green in colour. Oxide formed by V3+ i.e. V2O3 is basic in nature.

 



Q 28 :    

Among Sc, Mn, Co and Cu, identify the element with highest enthalpy of atomisation. The spin only magnetic moment value of that element in its +2 oxidation state is _____ B.M (in nearest integer).                [2025]



(4)

Element Sc Mn Co Cu
Enthalpy of atomization (kJ/mol) 326 281 425 339

 

Co has highest enthalpy of atomization among Sc, Mn, Co and Cu.

Co2+=[Ar]183d7, Number of unpaired electrons in Co2+(n) = 3.

Spin only magnetic moment (μ)

μ=n(n+2) BM

=3(3+2) BM=3.87 BM4 BM



Q 29 :    

Niobium (Nb) and ruthenium (Ru) have x and y number of electrons in their respective 4d orbitals. The value of x+y is _______.         [2025]



(11)

Nb41=[Kr]364d45s1

Ru44=[Kr]364d75s1

x+y=4+7=11



Q 30 :    

The spin only magnetic moment (μ) value (B.M.) of the compound with strongest oxidising power among Mn2O3, TiO and VO is _______ B.M. (Nearest integer).      [2025]



(5)

EMn3+/Mn2+=+1.57V,  EV2+/V=-1.18V,  ETi2+/Ti=-1.63V

As reduction potential of Mn3+ is more than that of V2+ and Ti2+Mn2O3 is a stronger oxidising agent than VO and TiO. 

Mn3+=18[Ar]3d4, number of unpaired electrons (n) = 4. 

Spin only magnetic moment (μ=n(n+2)BM

=4(4+2)BM=4.9 BM (nearest integer is 5)