Match List I with List II. d and f-Block Elements , (Spin only magnetic moment (B.M.))?? [2025]

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Q.
Match List I with List II. [2025]

List I List II

(Transition metal ion) (Spin only magnetic moment (B.M.))

A. ${Ti}^{3 +}$ I. 3.87

B. $V^{2 +}$ II. 0.00

C. ${Ni}^{2 +}$ III. 1.73

D. ${Sc}^{3 +}$ IV. 2.84

Choose the correct answer from the options given below:

1 A–III, B–I, C–IV, D–II

2 A–III, B–I, C–II, D–IV

3 A–IV, B–II, C–III, D–I

4 A–II, B–IV, C–I, D–III

Ans.
(1)

Transition metal ion Electronic configuration Number of unpaired electrons (n) Spin only magnetic moment ( $μ$ ) $= \sqrt{n (n + 2)}$ BM

${Ti}^{3 +}$ ${}_{18}{[Ar]}$ $3 d^{1}$ 1 $\sqrt{1 (1 + 2)} BM = 1.73 BM$

$V^{2 +}$ ${}_{18}{[Ar]}$ $3 d^{3}$ 3 $\sqrt{3 (3 + 2)} BM = 3.87 BM$

${Ni}^{2 +}$ ${}_{18}{[Ar]}$ $3 d^{8}$ 2 $\sqrt{2 (2 + 2)} BM = 2.83 BM$

${Sc}^{3 +}$ ${}_{18}{[Ar]}$ $3 d^{0}$ 0 $\sqrt{0 (0 + 2)} BM = 0 BM$

Solution

Q.
Match List I with List II. [2025]

List I List II

(Transition metal ion) (Spin only magnetic moment (B.M.))

A. ${Ti}^{3 +}$ I. 3.87

B. $V^{2 +}$ II. 0.00

C. ${Ni}^{2 +}$ III. 1.73

D. ${Sc}^{3 +}$ IV. 2.84

Choose the correct answer from the options given below:

1 A–III, B–I, C–IV, D–II

2 A–III, B–I, C–II, D–IV

3 A–IV, B–II, C–III, D–I

4 A–II, B–IV, C–I, D–III

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	List I		List II
	(Transition metal ion)		(Spin only magnetic moment (B.M.))
A.	${Ti}^{3 +}$	I.	3.87
B.	$V^{2 +}$	II.	0.00
C.	${Ni}^{2 +}$	III.	1.73
D.	${Sc}^{3 +}$	IV.	2.84

Transition metal ion	Electronic configuration	Number of unpaired electrons (n)	Spin only magnetic moment ( $μ$ ) $= \sqrt{n (n + 2)}$ BM
${Ti}^{3 +}$	${}_{18}{[Ar]}$ $3 d^{1}$	1	$\sqrt{1 (1 + 2)} BM = 1.73 BM$
$V^{2 +}$	${}_{18}{[Ar]}$ $3 d^{3}$	3	$\sqrt{3 (3 + 2)} BM = 3.87 BM$
${Ni}^{2 +}$	${}_{18}{[Ar]}$ $3 d^{8}$	2	$\sqrt{2 (2 + 2)} BM = 2.83 BM$
${Sc}^{3 +}$	${}_{18}{[Ar]}$ $3 d^{0}$	0	$\sqrt{0 (0 + 2)} BM = 0 BM$

Solution

Q. Match List I with List II. [2025] List I List II (Transition metal ion) (Spin only magnetic moment (B.M.)) A. Ti3+ I. 3.87 B. V2+ II. 0.00 C. Ni2+ III. 1.73 D. Sc3+ IV. 2.84 Choose the correct answer from the options given below:

1 A–III, B–I, C–IV, D–II

2 A–III, B–I, C–II, D–IV

3 A–IV, B–II, C–III, D–I

4 A–II, B–IV, C–I, D–III

Ans. (1) Transition metal ion Electronic configuration Number of unpaired electrons (n) Spin only magnetic moment (μ)=n(n+2)BM Ti3+ [Ar]183d1 1 1(1+2)BM=1.73 BM V2+ [Ar]183d3 3 3(3+2)BM=3.87 BM Ni2+ [Ar]183d8 2 2(2+2)BM=2.83 BM Sc3+ [Ar]183d0 0 0(0+2)BM=0 BM

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Q.
Match List I with List II. [2025]

List I List II

(Transition metal ion) (Spin only magnetic moment (B.M.))

A. ${Ti}^{3 +}$ I. 3.87

B. $V^{2 +}$ II. 0.00

C. ${Ni}^{2 +}$ III. 1.73

D. ${Sc}^{3 +}$ IV. 2.84

Choose the correct answer from the options given below: