Q 1 :    

Which of the following acts as a strong reducing agent?
(Atomic number : Ce = 58, Eu = 63, Gd = 64, Lu = 71)                      [2024]

  • Lu3+

     

  • Ce4+

     

  • Gd3+

     

  • Eu2+

     

(D)

Common oxidation state of Lanthanoids is +3. Ce4+ has tendency to go to Ce3+ hence Ce4+ is good oxidising agent. Eu2+ has tendency to go to Eu3+, hence is good reducing agent.

 



Q 2 :    

The number of element from the following that do not belong to lanthanoids is

 

Eu, Cm, Er, Tb, Yb and Lu                                   [2024]

  • 5

     

  • 1

     

  • 3

     

  • 4

     

(B)

Lanthanoid series elements are 

La57(Lanthanum), 58Ce(Cerium), 59Pr(Praseodymium), 60Nd(Neodymium), 61Pm(Promethium), Sm62(Samarium), 

63Eu(Europium), 64Gd(Gadolinium), 65Tb(Terbium), 66Dy(Dysprosium), Ho67(Holmium), 68Er(Erbium), 

69Tm(Thulium), 70Yb(Ytterbium), and 71Lu(Lutetium).

Cm96(Curium) is an actinoid.

 



Q 3 :    

The electronic configuration of Einsteinium is

 

(Given atomic number of Einsteinium = 99)                    [2024]

  • [Rn]5f126d07s2

     

  • [Rn]5f116d07s2

     

  • [Rn]5f136d07s2

     

  • [Rn]5f106d07s2

     

(B)

         Es99=[Rn]865f116d07s2

 



Q 4 :    

Number of colourless lanthanoid ions among the following is _________ .         

 

Eu3+,Lu3+,Nd3+,La3+,Sm3+                          [2024]



(2)

Lanthonoid ions are coloured because of f-f transitions.

Ions Electronic
configuration
f-f transition Colour
Eu3+ [Xe]544f6 possible Coloured
Lu3+ [Xe]544f14 Not possible as
there are no
unpaired f
electrons
Colourless
Nd3+ [Xe]544f3 possible Coloured
La3+ [Xe]544f0 Not possible as
there are no
f electrons
Colourless
Sm3+ [Xe]544f5 possible Coloured