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Solution


Q.

Niobium (Nb) and ruthenium (Ru) have “x” and “y” number of electrons in their respective 4d orbitals. The value of x+y is _______.         [2025]

Ans.

(11)

Nb41=[Kr]364d45s1

Ru44=[Kr]364d75s1

x+y=4+7=11