The wavelength of an electron of kinetic energy 4 . 50 × 10 - 29 J is ________ × 10 - 5 m . (Nearest integer) Given: mass of electron is 9 × 10 - 31 kg , h = 6 . 6 × 10 - 34 Js [2023]

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Solution

Q.
The wavelength of an electron of kinetic energy $4.50 \times 10^{- 29} J$ is ________ $\times 10^{- 5} m$ . (Nearest integer)

Given: mass of electron is $9 \times 10^{- 31} kg,$ $h = 6.6 \times 10^{- 34} Js$ [2023]

Ans.
(7)

$λ = \frac{h}{\sqrt{2 m K.E.}} = \frac{6.6 \times 10^{- 34}}{\sqrt{2 \times 9.1 \times 10^{- 31} \times 4.5 \times 10^{- 29}}}$

$= \frac{6.6 \times 10^{- 34}}{9.04 \times 10^{- 30}} = 7.3 \times 10^{- 5} \approx 7 \times 10^{- 5} m$

Where, $λ = Wavelength of an electron$

$h = Planck's constant$

$m = mass of electron$

$K.E. = Kinetic energy of electron$

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