(x² + 1)² ? x² = 0 has:

Question

$(x ² + 1) ² - x ² = 0 h a s$

Smart Achievers · Accepted Answer

(3)

Given equation: $(x ² + 1) ² - x ² = 0 \Rightarrow (x ² + 1 - x) (x ² + 1 + x) = 0 .$

$\Rightarrow (x ² - x + 1) (x ² + x + 1) = 0 o r x ² - x + 1 = 0,$
$I t s d i s c r i m i n a n t D = (- 1) ² - 4 \times 1 \times 1 = - 3 < 0$
$I t s d i s c r i m i n a n t D = 1 ² - 4 \times 1 \times 1 = - 3 < 0$

So, there are no real roots.

Solution

Q.
$(x ² + 1) ² - x ² = 0 h a s$

1 Four real roots

2 Two real roots

3 No real roots

4 One real root

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