Which of the following statements are correct with respect to [ N i C l 4 ] 2 - and [ N i ( P P h 3 ) 2 C l 2 ] ?

Question

Which of the following statements are correct with respect to ${[N i C l_{4}]}^{2 -}$ and $[N i {(P P h_{3})}_{2} C l_{2}]$ ?

Smart Achievers · Accepted Answer

(2)

${Cl}^{-}$ is a weak ligand, so no pairing of electrons takes place. So, ${[{NiCl}_{4}]}^{2 -}$ is tetrahedral. The ${PPh}_{3}$ group is bulkier one so it favours tetrahedral geometry, through ${PPh}_{3}$ is a strong-field ligand.

Solution

Q.
Which of the following statements are correct with respect to ${[N i C l_{4}]}^{2 -}$ and $[N i {(P P h_{3})}_{2} C l_{2}]$

1 In both cases Ni undergoes $d s p^{2}$ hybridisation.

2 $[N i {(P P h_{3})}_{2} C l_{2}]$ is tetrahedral.

3 $[N i {(P P h_{3})}_{2} C l_{2}]$ is square planar.

4 ${[N i C l_{4}]}^{2 -}$ is square planar.

Ans.
(2)

${Cl}^{-}$ is a weak ligand, so no pairing of electrons takes place. So, ${[{NiCl}_{4}]}^{2 -}$ is tetrahedral. The ${PPh}_{3}$ group is bulkier one so it favours tetrahedral geometry, through ${PPh}_{3}$ is a strong-field ligand.

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Solution

Q. Which of the following statements are correct with respect to [NiCl4]2- and [Ni(PPh3)2Cl2]

1 In both cases Ni undergoes dsp2 hybridisation.

2 [Ni(PPh3)2Cl2] is tetrahedral.

3 [Ni(PPh3)2Cl2] is square planar.

4 [NiCl4]2- is square planar.

Ans. (2) Cl- is a weak ligand, so no pairing of electrons takes place. So, [NiCl4]2- is tetrahedral. The PPh3 group is bulkier one so it favours tetrahedral geometry, through PPh3 is a strong-field ligand.