Which of the following is correct order of ligand field strength? [2023]

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Q.
Which of the following is correct order of ligand field strength [2023]

1 $S^{2 -} > {NH}_{3} < en < CO < C_{2} O_{4}^{2 -}$

2 ${NH}_{3} < en < CO < S^{2 -} < C_{2} O_{4}^{2 -}$

3 $CO < en < {NH}_{3} < C_{2} O_{4}^{2 -} < S^{2 -}$

4 $S^{2 -} < C_{2} O_{4}^{2 -} < {NH}_{3} < en < CO$

Ans.
(4)

From spectrochemical series, the increasing order of field strength of ligands is:

$I^{-} < {Br}^{-} < {SCN}^{-} < {Cl}^{-} < S^{2 -} < F^{-} < {OH}^{-} < C_{2} O_{4}^{2 -} < H_{2} O < {NCS}^{-} < {edta}^{4 -} < {NH}_{3} < en < {CN}^{-} < CO$

Solution

Q.
Which of the following is correct order of ligand field strength [2023]

1 $S^{2 -} > {NH}_{3} < en < CO < C_{2} O_{4}^{2 -}$

2 ${NH}_{3} < en < CO < S^{2 -} < C_{2} O_{4}^{2 -}$

3 $CO < en < {NH}_{3} < C_{2} O_{4}^{2 -} < S^{2 -}$

4 $S^{2 -} < C_{2} O_{4}^{2 -} < {NH}_{3} < en < CO$

Ans.
(4)

From spectrochemical series, the increasing order of field strength of ligands is:

$I^{-} < {Br}^{-} < {SCN}^{-} < {Cl}^{-} < S^{2 -} < F^{-} < {OH}^{-} < C_{2} O_{4}^{2 -} < H_{2} O < {NCS}^{-} < {edta}^{4 -} < {NH}_{3} < en < {CN}^{-} < CO$

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Solution

Q. Which of the following is correct order of ligand field strength [2023]

1 S2->NH3<en<CO<C2O42-

2 NH3<en<CO<S2-<C2O42-

3 CO<en<NH3<C2O42-<S2-

4 S2-<C2O42-<NH3<en<CO

Ans. (4) From spectrochemical series, the increasing order of field strength of ligands is: I-<Br-<SCN-<Cl-<S2-<F-<OH-<C2O42-<H2O<NCS-<edta4-<NH3<en<CN-<CO

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Q.
Which of the following is correct order of ligand field strength [2023]

1 $S^{2 -} > {NH}_{3} < en < CO < C_{2} O_{4}^{2 -}$

2 ${NH}_{3} < en < CO < S^{2 -} < C_{2} O_{4}^{2 -}$

3 $CO < en < {NH}_{3} < C_{2} O_{4}^{2 -} < S^{2 -}$

4 $S^{2 -} < C_{2} O_{4}^{2 -} < {NH}_{3} < en < CO$

Ans.
(4)

From spectrochemical series, the increasing order of field strength of ligands is:

$I^{-} < {Br}^{-} < {SCN}^{-} < {Cl}^{-} < S^{2 -} < F^{-} < {OH}^{-} < C_{2} O_{4}^{2 -} < H_{2} O < {NCS}^{-} < {edta}^{4 -} < {NH}_{3} < en < {CN}^{-} < CO$