When one moves from a point 16 km below the earth’s surface to a point 16 km above the earth’s surface

Question

When one moves from a point 16 km below the earth’s surface to a point 16 km above the earth’s surface. The change in $g$ is approximately $α %$ . The value of $α$ is ______.

(Take radius of the earth = 6400 km) [2026]

Smart Achievers · Accepted Answer

(2)

$g_{below} = g (1 - \frac{16}{6400})$

$g_{above} = g (1 - \frac{2 \times 16}{6400})$

$Δ g = g_{below} - g_{above}$

$Δ g = g (1 - \frac{16}{6400}) - g (1 - \frac{32}{6400})$

$Δ g = g (\frac{16}{6400})$

$Hence percentage change in g is$

$= \frac{Δ g}{g} \times 100 = \frac{16}{6400} \times 100 = 0.25 %$

Solution

Q.
When one moves from a point 16 km below the earth’s surface to a point 16 km above the earth’s surface. The change in $g$ is approximately $α %$ . The value of $α$ is ______.

(Take radius of the earth = 6400 km) [2026]

1 0.12

2 0.25

3 0.50

4 0.75

Want Us to Email you About Special Offers & Updates?