Q.

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper. The distance of each wire from the centre of the loop is d. The loop and the wires are carrying the same current I. The current in the loop is in the counterclockwise direction if seen from above.

Q.    When d≈a but wires are not touching the loop, it is found that the net magnetic field on the axis of the loop is zero at a height h above the loop. In that case         [2014]

1 current in wire 1 and wire 2 in the direction PQ and RS, respectively and h≈a  
2 current in wire 1 and wire 2 in the direction PQ and SR, respectively and h≈a  
3 current in wire 1 and wire 2 in the direction PQ and SR, respectively and h≈1.2a  
4 current in wire 1 and wire 2 in the direction PQ and RS, respectively and h≈1.2a  

Ans.

(3)

Here B1sinθ and B2sinθ cancelled each other.

For zero magnetic field at 'P'

Magnetic field due to current carrying circular loop = Magnetic field due to straight wires

B=B1cosθ+B2cosθ=2B1cosθ

μ0Ia22(a2+h2)3/2=2[μ0I2πa2+h2]×aa2+h2

Solving we get,

h≈1.2a

The current is from P to Q and R to S in wire 1 and wire 2 respectively.