When a uranium isotope is bombarded with a neutron, it generates , three neutrons and [2020]

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Solution

Q.
When a uranium isotope ${}_{92}^{235}U$ is bombarded with a neutron, it generates ${}_{36}^{89}{Kr}$ , three neutrons and [2020]

1 ${}_{56}^{144}{Ba}$

2 ${}_{40}^{91}{Zr}$

3 ${}_{36}^{101}{Kr}$

4 ${}_{36}^{103}{Kr}$

Ans.
(1)

${}_{92}{U^{235}} + {}_{0}{n^{1}} ⟶ {}_{36}{Kr}^{89} + 3 n_{0}^{1} + {}_{Z}{X^{A}}$

$92 + 0 = 36 + Z \Rightarrow Z = 56$

Now, $235 + 1 = 89 + 3 + A \Rightarrow A = 144$

So, ${}_{56}{Ba}^{144}$ is generated.

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