What is the mass ratio of ethylene glycol (, molar mass = 62 g/mol) required for making 500 g of 0.25 molal aqueous solution and 250 mL of 0.25 molal aqueous solution? [2023]

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Solution

Q.
What is the mass ratio of ethylene glycol ( $C_{2} H_{6} O_{2}$ , molar mass = 62 g/mol) required for making 500 g of 0.25 molal aqueous solution and 250 mL of 0.25 molal aqueous solution [2023]

1 1 : 2

2 1 : 1

3 3 : 1

4 2 : 1

Ans.
(4)

$\frac{Millimoles of 1st case}{Millimoles of 2nd case} = \frac{500 \times 0.25}{250 \times 0.25} = \frac{2}{1} = 2 : 1$

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