Value of sec sin of Class 10 Maths Introduction to Trigonometry questions with solutions

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Solution

Q.
If $\sin θ = \cos θ,$ $(0 ° < θ < 90 °),$ then value of $(\sec θ . \sin θ)$ is:

1 $1 / \sqrt{2}$

2 $\sqrt{2}$

3 $1$

4 $0$

Ans.
(3)

$\sin θ = \cos θ \Rightarrow \tan θ = 1 = 45 ° \Rightarrow θ = 45 °$

Now, $\sec θ . \sin θ = \sec 45 ° . \sin 45 ° = \sqrt{2} \times \frac{1}{\sqrt{2}} = 1$

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