Two resistors of 200 and 400 are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected

Question

Two resistors of 200 $Ω$ and 400 $Ω$ are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected across the 400 $Ω$ resistance. The potential drop across the bulb is _____ V. [2026]

Smart Achievers · Accepted Answer

(2)

$For resistance of bulb$

$R = \frac{V^{2}}{P} = \frac{200 \times 200}{100} = 400 Ω$

$R_{eq} = (200 + 200) Ω = 400 Ω$

$I = \frac{100}{400} = \frac{1}{4} A$

$V_{bulb} = \frac{1}{4} \times 200 = 50 V$

Solution

Q.
Two resistors of 200 $Ω$ and 400 $Ω$ are connected in series with a battery of 100 V. A bulb rated at 200 V, 100 W is connected across the 400 $Ω$ resistance. The potential drop across the bulb is _____ V. [2026]

1 25

2 50

3 66.6

4 100

Ans.
(2)

$For resistance of bulb$

$R = \frac{V^{2}}{P} = \frac{200 \times 200}{100} = 400 Ω$

$R_{eq} = (200 + 200) Ω = 400 Ω$

$I = \frac{100}{400} = \frac{1}{4} A$

$V_{bulb} = \frac{1}{4} \times 200 = 50 V$

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