Two positively charged particles have been accelerated across the same potential difference of 200 keV as shown below. [Given mass of amu] The deBroglie wavelength of will be x times of. The va

Question

Two positively charged particles $m_{1} and m_{2}$ have been accelerated across the same potential difference of 200 keV as shown below.

[Given mass of $m_{1} = 1 amu and m_{2} = 4$ amu]

The deBroglie wavelength of $m_{1}$ will be x times of $m_{2}$ . The value of x is __________ (nearest integer). [2026]

Smart Achievers · Accepted Answer

(2)

$λ_{d} = \frac{h}{\sqrt{2 m K.E.}}$

$Here K.E. is same i.e. 200 keV$

$So λ_{d} \propto \frac{1}{\sqrt{m}}$

$m_{2}$

${(λ_{d})}_{m_{1}} = 2 {(λ_{d})}_{m_{2}}$

$So x = 2$

Want Us to Email you About Special Offers & Updates?