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Solution


Q.

Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce  F₁ progeny that have round yellow (RrYy) seeds. When F₁ plants are self-pollinated, the F₂ progeny will have a new combination of characters. Choose the new combinations from the following:

(i) Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv) Wrinkled, green
1 (i) and (ii)  
2 (i) and (iv)  
3 (ii) and (iii)  
4 (i) and (iii)  

Ans.

(2)

The new combination in F₂ progeny will be round yellow and wrinkled green. The phenotypic ratio obtained in a dihybrid cross is 9:3:3:1.
The phenotypic ratio will be – Round Yellow: Round green: Wrinkled yellow: Wrinkled green = 9:3:3:1