Q.

Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in figure. The whole system is going upwards with an acceleration of 2 m s-2. The tensions T1 and T2 are respectively (Take g = 10 m s-2)

1 96 N, 36 N  
2 36 N, 96 N  
3 96 N, 96 N  
4 36 N, 36 N  

Ans.

(1)

The free body diagram of 3 kg block is as shown in the figure (a).

The equation of motion of 3 kg block is

T2-3g=3a

T2=3(a+g)=3(2+10)=36 N              ⋯(i)

The free body diagram of 5 kg is as shown in the figure (b).

The equation of motion of 5 kg block is

T1-T2-5g=5a

T1=5(a+g)+T2

      =5(2+10)+36=96 N             (Using (i))