Q.

Two liquids A and B have θA and θB as contact angles in a capillary tube. If K=cos θA/cos θB, then identify the correct statement:          [2025]

1 K is negative, then liquid A and liquid B have convex meniscus.  
2 K is negative, then liquid A and liquid B have concave meniscus.  
3 K is negative, then liquid A has concave meniscus and liquid B has convex meniscus.  
4 K is zero, then liquid A has convex meniscus and liquid B has concave meniscus.  

Ans.

(3)

For concave meniscus θA < 90°

For convex meniscus θB > 90°

K=cos θAcos θB<0

K is negative when cos θA and  cos θB are of opposite signs.