Two infinite identical charged sheets and a charged spherical body of charge density ' $ρ$ ' are arranged as shown in figure. Then the correct relation between the electrical fields at A, B, C and D points is: [2025]

Question

Smart Achievers · Accepted Answer

(3)

At points A and B sum of field due to plates is zero.

A is closer to the body so ${\vec{E}}_{A} > {\vec{E}}_{B}$ .

D and C are not symmetric w.r.t. body so $E_{C} \neq E_{D}$

Solution

Q.
Two infinite identical charged sheets and a charged spherical body of charge density ' $ρ$ ' are arranged as shown in figure. Then the correct relation between the electrical fields at A, B, C and D points is: [2025]

1 ${\vec{E}}_{A} = {\vec{E}}_{B}; {\vec{E}}_{C} = {\vec{E}}_{D}$

2 ${\vec{E}}_{A} > {\vec{E}}_{B}; {\vec{E}}_{C} = {\vec{E}}_{D}$

3 ${\vec{E}}_{C} \neq {\vec{E}}_{D}; {\vec{E}}_{A} > {\vec{E}}_{B}$

4 $| {\vec{E}}_{A} | = | {\vec{E}}_{B} |; {\vec{E}}_{C} > {\vec{E}}_{D}$

Ans.
(3)

At points A and B sum of field due to plates is zero.

A is closer to the body so ${\vec{E}}_{A} > {\vec{E}}_{B}$ .

D and C are not symmetric w.r.t. body so $E_{C} \neq E_{D}$

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Solution

Q. Two infinite identical charged sheets and a charged spherical body of charge density 'ρ' are arranged as shown in figure. Then the correct relation between the electrical fields at A, B, C and D points is: [2025]

1 E→A=E→B; E→C=E→D

2 E→A>E→B; E→C=E→D

3 E→C≠E→D; E→A>E→B

4 |E→A|=|E→B|; E→C>E→D

Ans. (3) At points A and B sum of field due to plates is zero. A is closer to the body so E→A>E→B. D and C are not symmetric w.r.t. body so EC≠ED