Two identical small bar magnets each of dipole moment are placed at a center to center separation of 10 cm

Question

Two identical small bar magnets each of dipole moment $3 \sqrt{5} J/T$ are placed at a center to center separation of 10 cm, with their axes perpendicular to each other as shown in figure. The value of magnetic field at the point $P$ midway between the magnets is $α \times 10^{- 3} T$ . The value of $α$ is ______. $(μ_{0} = 4 π \times 10^{- 7} Tm/A)$ [2026]

Smart Achievers · Accepted Answer

(12)

$B_{n e t} = \sqrt{B_{1}^{2} + B_{2}^{2}} = \frac{μ_{0}}{4 π} \frac{M}{{(r)}^{3}} \sqrt{5}$

$= 10^{- 7} \times 3 \sqrt{5} \times \sqrt{5} \times \frac{8}{10^{- 3}}$

$= 120 \times 10^{- 4} = 12 mT$

Solution

Ans.
(12)

$B_{n e t} = \sqrt{B_{1}^{2} + B_{2}^{2}} = \frac{μ_{0}}{4 π} \frac{M}{{(r)}^{3}} \sqrt{5}$

$= 10^{- 7} \times 3 \sqrt{5} \times \sqrt{5} \times \frac{8}{10^{- 3}}$

$= 120 \times 10^{- 4} = 12 mT$

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Solution

Ans. (12) Bnet=B12+B22=μ04πM(r)35 =10-7×35×5×810-3 =120×10-4=12 mT

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Ans.
(12)

$B_{n e t} = \sqrt{B_{1}^{2} + B_{2}^{2}} = \frac{μ_{0}}{4 π} \frac{M}{{(r)}^{3}} \sqrt{5}$

$= 10^{- 7} \times 3 \sqrt{5} \times \sqrt{5} \times \frac{8}{10^{- 3}}$

$= 120 \times 10^{- 4} = 12 mT$