Two dice are rolled together. The probability of getting sum of numbers on the two dice as 2, 3 or 5, is:
(1)
When two dice are tossed together,
Total possible outcomes = 62 = 36
No. of cases getting sum two : {(1, 1)}
No. of cases getting sum three : {(1, 2)(2, 1)}
No. of cases getting sum five : {(1, 4)(4, 1), (2, 3), (3, 2)}
Thus total cases getting sum 2, 3 or 5 = 7
Therefore, required probability = 7/36