Two coins are tossed together. The probability of getting at least one tail is:
(3)
When two coins are tossed, the total possible outcomes are S=HT,TH,HH,TT⇒n(S)=4
The outcomes favourable to event E‘at least one tail’ are E=TH,HT,TT⇒n(E)=3
∴ The probability of getting at least one tail P(E)=n(E)n(S)=34