Q.

Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xP(t)=(at+bt2) and xQ(t)=(ft-t2). At what time do the cars have the same velocity              [2016]

1 a-f1+b  
2 a+f2(b-1)  
3 a+f2(1+b)  
4 f-a2(1+b)  

Ans.

(4)

Position of the car P at any time t, is

xP(t)=at+bt2;  vP(t)=dxP(t)dt=a+2bt                         ...(i)

Similarly, for car Q,

xQ(t)=ft-t2;  vQ(t)=dxQ(t)dt=f-2t                             ...(ii)

  vP(t)=vQ(t)  (Given)

  a+2bt=f-2t or, 2t(b+1)=f-a  

  t=f-a2(1+b)