Two batteries of different emfs and different internal resistances are connected as shown. The voltage across AB in volts is [2011]

Question

Smart Achievers · Accepted Answer

(5)

$Let i be the current flowing in the circuit. Applying Kirchhoff's law (KVL) in the loop C D E F C,$

$- 3 - 2 i - i + 6 = 0$ $\Rightarrow 3 i = 3$

$∴$ $i = 1 A$

$Now for upper or lower path$

$V_{A} - 6 + 1 \times 1 = V_{B}$

$∴$ $V_{A} - V_{B} = 5 V$

$or,$ $V_{A} - 3 - 2 \times 1 = V_{B}$

$∴$ $V_{A} - V_{B} = 5 V$

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