To measure the temperature coefficient of resistivity of a semiconductor, an electrical arrangement shown in the figure is prepared. The arm BC is made up of the semiconductor. The experinment is being conducted at 25 °C and resistance of the semiconduct

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Q.
To measure the temperature coefficient of resistivity $α$ of a semiconductor, an electrical arrangement shown in the figure is prepared. The arm BC is made up of the semiconductor. The experiment is being conducted at 25 °C and resistance of the semiconductor arm is 3 $m Ω$ . Arm BC is cooled at a constant rate of 2° C/s. If the galvanometer G shows no deflection after 10 s, then $α$ is [2024]

1 $- 1 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

2 $- 2 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

3 $- 2.5 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

4 $- 1.5 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

Ans.
(1)

For no. deflection $= \frac{0.8}{1} = \frac{R}{3}$

$R = 2.4 m Ω$

$Δ R = R α Δ T$

$\Rightarrow α = \frac{Δ R}{R Δ T} = \frac{- 0.6}{3 \times 20} = - 10^{- 2}$ ${}^{o}{C^{- 1}}$

Solution

1 $- 1 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

2 $- 2 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

3 $- 2.5 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

4 $- 1.5 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

Ans.
(1)

For no. deflection $= \frac{0.8}{1} = \frac{R}{3}$

$R = 2.4 m Ω$

$Δ R = R α Δ T$

$\Rightarrow α = \frac{Δ R}{R Δ T} = \frac{- 0.6}{3 \times 20} = - 10^{- 2}$ ${}^{o}{C^{- 1}}$

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Solution

1 -1×10-2C-1o

2 -2×10-2C-1o

3 -2.5×10-2C-1o

4 -1.5×10-2C-1o

Ans. (1) For no. deflection =0.81=R3 R=2.4 mΩ ΔR=RαΔT ⇒α=ΔRRΔT=-0.63×20=-10-2C-1o

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1 $- 1 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

2 $- 2 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

3 $- 2.5 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

4 $- 1.5 \times 10^{- 2}$ ${}^{o}{C^{- 1}}$

Ans.
(1)

For no. deflection $= \frac{0.8}{1} = \frac{R}{3}$

$R = 2.4 m Ω$

$Δ R = R α Δ T$

$\Rightarrow α = \frac{Δ R}{R Δ T} = \frac{- 0.6}{3 \times 20} = - 10^{- 2}$ ${}^{o}{C^{- 1}}$